mavvenegas18 mavvenegas18
  • 23-05-2018
  • Mathematics
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f(x)= -x-2, g(x)=x^2, what is (g°f)(-6)

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hisroyal1
hisroyal1 hisroyal1
  • 23-05-2018
f(x) = -x - 2
g(x) = x^2

(g°f)(-6) = ?

First, we find f(-6)
f(x) = -x - 2
f(-6) = -(-6) - 2
f(-6) = 6 - 2
f(-6) = 4

Since f(-6) = 4,
(g°f)(-6) = g(4)

g(x) = x^2
g(4) = 4^2
g(4) = 16

Therefore, (g°f)(-6) = 16
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