Respuesta :

gmany

[tex]ax^2+bx+c=0\\\\x_1\cdot x_2=\dfrac{c}{a}[/tex]

We have:

[tex]8x^2-2x=1\ \ \ |-1\\\\8x^2-2x-1=0\\\\a=8;\ b=-2;\ c=-1\\\\x_1\cdot x_2=\dfrac{-1}{8}=-\dfrac{1}{8}[/tex]