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25-07-2019
Chemistry

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How many moles of Fe304 are required to supply enough iron to prepare 0.171 mol Fe203?

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MathPhys MathPhys

25-07-2019

Answer:

0.114 moles

Explanation:

Calculate available moles of Fe:

0.171 mol Fe₂O₃ × (2 mol Fe / mol Fe₂O₃) = 0.342 mol Fe

Now calculate moles of Fe₃O₄ needed:

0.342 mol Fe × (1 mol Fe₃O₄ / 3 mol Fe) = 0.114 mol Fe₃O₄

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