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What is the minimum magnitude of an electric field that balances the weight of a plastic sphere of mass 14.2 g that has been charged to 7.7 nC. Give your answer to the nearest 0.1 MN/C (mega Newton per Coulomb)

Respuesta :

Answer: 18 MN/C

Explanation: Taking into account the weigth (m* g) and electric force for a charge in a electric fiel as (q*E) both are equals

so 0.0142 Kg*9.8 m/s^2= q*E

thus E= (0.0142*9.8)/(7.7*10^-9)