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A 110 kg crate is pulled along a level surface by an engine. The coefficient of kinetic friction between the crate and the surface is 0.585. How much power must the engine deliver to move the crate at a constant speed of 7.59 m/s? The acceleration due to gravity is 9.8 m/s 2 . Answer in units of W.

Respuesta :

Answer:

Net power will be 1150.637 watt

Explanation:

We have given mass of the crate m = 110 kg

Coefficient of friction [tex]\mu =0.585[/tex]

Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]

Constant speed [tex]v=7.59m/sec[/tex]

Force applied [tex]F=ma=110\times 7.59=834.9N[/tex]

Frictional force [tex]f=\mu mg=0.585\times 110\times 9.8=630.63N[/tex]

So net force [tex]=834.9-630.6=204.3N[/tex]

Power is given by [tex]P=Fv=204.3\times 7.59=1550.637Watt[/tex]

So net power will be 1550.637 watt

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