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Two objects separated by a distance r are each carrying a charge q The magnitude of the force exerted on the second object by the first is F If the first object is removed and replaced with an identical object that carries a charge 4q what is the magnitude of the electric force on the second object

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samuelonum1

Answer:F=4F

Explanation: Columbs law states that The force between the two point charges is directly proportional to the product of charges and inversely proportional to the square of distance between them

Force between the two charges is given by

F=K*q1*q2/r^2

if one charge become 4 times, new force is,

F=4(K*q1*q2)/r^2

F=4F

Where q1 and q2 are the point charges

r is the distance between the two charges

K is a constant of proportion called electrostatic force

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