Answer:
The frequency of the oscillations in terms of fo will be f2=fo/3
E xplanation:
T= [tex] 2pie\frac sqrt {m}{k}[/tex]
[tex]\frac {{f2}/times {fo}} [/tex]=1:3
⇒f2=fo\3
Here frequency f is inversely poportional to square root of mass m.
so the value of remainder of frequency f2 and fo is equal to 1:3.
⇒[tex]\frac{f2} {f1}[/tex] = [tex] \frac sqrt{m1}[m2}[/tex]
⇒[tex]\frac{f2}{fo}[/tex] = 1:3
⇒f2=[tex]\frac{fo} {3}[/tex]
