A truck drives with a constant linear speed v_iv i v, start subscript, i, end subscript down a road with two curves. The first curve has a radius RRR and the second curve has a radius 3R3R3, R. How does the magnitude of the truck's centripetal acceleration change after the radius increases? Choose 1 answer: Choose 1 answer: (Choice A) A Increases by factor of 333 (Choice B) B Decreases by factor of 999 (Choice C) C Decreases by factor of 333 (Choice D) D No change

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adelekeademolu adelekeademolu · Answer 1 · 2020-03-26T01:41:41+01:00

Answer:

(C) Decreases by factor of 3

Explanation:

Centripetal acceleration is given by

[tex]a = \dfrac{v^2}{r}[/tex]

where v is the linear velocity and r is the radius of the curve.

Let the centripetal acceleration on the curve of radius R be [tex]a_1[/tex].

Then

[tex]a_1 = \dfrac{v_i^2}{R}[/tex]

Let the centripetal acceleration on the curve of radius 3R be [tex]a_2[/tex].

Then

[tex]a_2 = \dfrac{v_i^2}{3R} = \dfrac{1}{3}\dfrac{v_i^2}{R} = \dfrac{1}{3}a_1[/tex]

Here, we see that the acceleration decreases by a factor of 3.