Respuesta :

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[tex]\displaystyle \\ m\ \textless \ ABE + m\ \textless \ EBD = m\ \textless \ ABD \\ \\ (2x - 5)^o + (x + 1)^o = 50^o \\ \\ 2x-5+x+1=50 \\ \\ 3x - 4 = 50 \\ \\ 3x = 50+4 \\ \\ 3x = 54 \\ \\ x = \frac{54}{3} = \boxed{18^o}[/tex]