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In Omarion's bag of M&Ms, 1/3 were red, 1/4 were yellow, 1/6 were blue, and 1/4 were orange. He picks out a candy without looking. What color candy is he least likely to choose?

Respuesta :

medinegenc091

Answer:

RED

Step-by-step explanation:

  • First of all, we will make all candies common, so we will expand the denominators.

1/3  

1/4

1/6

1/4

  • all equal at 12
  • So there is a total of 12 candies
  • then the new version of the candies is

4/12

3/12

2/12

3/12

  • the most red sugar

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