Answer:
Explanation:
Given
initial velocity u = 0m/s
Distance of fall S = 1.0m
Final velocity = ?
a is the acceleration due to gravity = 9.81m/s²
Using the equation of motion
v² = u² + 2aS
v² = 0+2(9.81)(1)
v² = 19.62
v = √19.62
v = 4.43m/s
Hence the velocity of the book just before it hits the ground is 4.43m/s
