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Consider the following triangle:
Part A:find the perimeter of the triangle:
Options__
1) 72^1/2+32^1/2+2.16^1/3
2) 72^1/2+32^1/2+32^1/3
3) 104^1/2+2.16^1/3
Part B: Ronnie correctly rewrote the perimeter using radicals. Which expression did he use?
1) √32+ √72+3^ √16
2) √32+ √72+ √16
3) √32+ √72+3^ √32
4) √32+ √72+2 3^ √16

Part c in graph...if you already know the answer for it..please let me know

Consider the following triangle Part Afind the perimeter of the triangle Options 1 7212321221613 2 721232123213 3 1041221613 Part B Ronnie correctly rewrote the class=

Respuesta :

ssbmgill

Answer:

Part A: B

Part B: I think 3

Step-by-step explanation:

Simply for Part A, put all the numbers together and add them for 2*16^1/3, you just multiply the 2 and 16. For the second part, use process of elimination

HOPE THIS HELPS:

SSG

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