Answer:
The final speed of the bicyclist is 15.44 m/s.
Explanation:
Given;
initial velocity, u = 0
time of motion, t = 4.8 s
distance covered, d = 37.0 m
The acceleration of the bicyclist is calculated as;
d = ut + ¹/₂at²
37 = 0 + ¹/₂(4.8)²a
37 = 11.52a
a = 37 / 11.5
a = 3.22 m/s²
The final speed of the bicyclist is given as;
v² = u² + 2ad
v² = 0 + 2(3.22)(37)
v² = 238.28
v = √238.28
v = 15.44 m/s
Therefore, the final speed of the bicyclist is 15.44 m/s.
