The angle of depression from the top of a 150 m high cliff to a boat at sea is 7 degrees. How much closer to the cliff must the boat move for the angle of depression to become 19 degrees ...?
The first thing we need to do is use tan to find x. If the original angle of depression is 7 degrees, then the angle from the cliff to the bow of the boat is 90-7=83 degrees. Thus,tan83 = d / 150or we can express it like this:d =150 tan 83 ≈ 855.2where d is the total distance from the boat to the cliff when the angle of depression is 7 degrees. Hope this helps a lot
