You roll a fair six-sided die twice. Find the probability of rolling a 2 the first time and a number greater than 1 the second time.

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Answer:

for finding a 2 it would be 2/12 then for finding a number greater than 1 it would be 10/12. 16.6666...%=2/12  10/12=83.33333333...%

Step-by-step explanation: