Calculate the number of moles of iron (III) oxide (Fe 2 O 3 ) produced from 112 L of oxygen
(O 2 ) in the following reaction

4Fe(s) + 3O2 (g) = 2Fe2O3 (s)

Respuesta :

112 L/ 16 L = 7 mol O2

7 mol O2 x 2 mol Fe2O3/ 3 mol O2 = 4.67 mol Fe2O3

lmk if its right