contestada

Which of the following is a solution to 2sin^2x+sinx-1=0?
A. 45 degrees
B. 200 degrees
C. 240 degrees
D. 270 degrees
E. 330 degrees

Respuesta :

beinggreat78

Answer

[tex]x = \frac{\pi }{6} + 2\pi n, \frac{5\pi }{6} + 2\pi n, \frac{3\pi }{2} + 2\pi n[/tex], for any integer n

Answer:

D or 270°

Step-by-step explanation:

2sin^2x+sinx-1

2sin^2(270°)+sin(270°)-1=0