12
1) In this case, we have two chords within that circle. And since the arc = 64º and the m ∠ABC = 4x -16
2) Applying one Theorem that states that
3) So we can write:
[tex]\begin{gathered} (4x-16)\text{ =}\frac{64}{2} \\ 4x-16\text{ =32} \\ 4x\text{ =32+16} \\ 4x\text{ = 48} \\ x=12 \end{gathered}[/tex]
So the value of x = 12
