Given:
The lamp draws the current is
[tex]I=0.50\text{ A}[/tex]The voltage supplied by the generator is
[tex]V=120\text{ V}[/tex]The time for which energy converted is
[tex]\begin{gathered} t=5\text{ min} \\ t=5\times60\text{ s} \\ t=300\text{ s} \end{gathered}[/tex]Explanation:
(a)
The power delivered by the generator is given by
[tex]P=VI[/tex]Plugging all the values in the above equation, we get
[tex]\begin{gathered} P=120\text{ V}\times0.50\text{ A} \\ P=60\text{ watt} \end{gathered}[/tex]The power delivered by the generator is
[tex]60\text{ watt}[/tex](b)
Energy is converted by the electric lamp is given by
[tex]E=Pt[/tex]Plugging all the values in the above relation, we get
[tex]\begin{gathered} E=60\text{ watt}\times300\text{ s} \\ E=18000\text{ J} \end{gathered}[/tex]Thus, the electric energy convert by the lamp is
[tex]18000\text{ J}[/tex]