apartment building has the following distribution of apartments:1 bedroom2 bedroom3 bedroom1st floor3212nd floor1323rd floor141If an apartment is selected at random, what is the probability that it is on the 2nd floor or has 2 bedrooms?

Given
[tex]\text{Probability}=\frac{possible\text{ outcome }}{\text{Total }outcome}[/tex]The total outcome is 3+1+1+1+3+4+1+2+1=17
All 2nd floor apartment 1+3+2 =6
All apartment with 2 bedroom = 1+3+4=8
[tex]\begin{gathered} \text{Probability selecting an apartment in }2ndfloor\text{ or has 2bedroom =}\frac{6}{17}+\frac{8}{17} \\ \text{Probability selecting an apartment in }2ndfloor\text{ or has 2bedroom }=\frac{14}{17} \\ \text{Probability selecting an apartment in }2ndfloor\text{ or has 2bedroom }=0.82352941176 \end{gathered}[/tex]The final answer
[tex]\text{Probability selecting an apartment in }2ndfloor\text{ or has 2bedroom}=0.82352941176[/tex]