D. Multiply both sides of the top equation by 3
Explanation
[tex]\begin{gathered} 4x+2y=4 \\ 12x+y=22 \end{gathered}[/tex]to do that, both equations must have equal x-coeeficient, we need
Step 1
check the coefficients
[tex]\begin{gathered} 4x+2y=4\Rightarrow x\text{ coefficient is 4} \\ 12x+y=22\Rightarrow x\text{ coefficient is 12} \end{gathered}[/tex][tex]\begin{gathered} c_1=4 \\ c_2=12 \end{gathered}[/tex]Now, to go from C1 ( 4) to C2( 12) we can multiply the top eqution by 3 , this way we would get
[tex]\begin{gathered} 3\cdot c_1=12 \\ 3\cdot c_1=c_2 \\ 12=12 \end{gathered}[/tex]or
to go from C2 ( 12) to C1 ( 3) we can divide the bottom equation by 3
[tex]\begin{gathered} c_1=\frac{1}{3}\cdot c_2 \\ 4=\frac{12}{3} \\ 4=4 \end{gathered}[/tex]therefore, the anwer is
D. Multiply both sides of the top equation by 3
[tex]3\cdot(4x+2y=4)\Rightarrow12x+8y=12[/tex]now it has 12 as coefficient for x
I hope this helps you
