Quadratic Equations: ax^2+bx+c=0
Factor first mult. A and C then use the factors from the answer to add to B
1.) 2b^2+10b+12
2.) 3g^2+8g+4
3.) 4x^2+4x-3
4.) 8b^2-5b-10
5.) 6m^2+7m-3
6.) 10d^2+17d-20
Please Answer ASAP Show ALL WORK
quadratic equaiton is x=[tex] \frac{-b- \sqrt{b^2-4ac} }{2a} [/tex] or [tex] \frac{-b+ \sqrt{b^2-4ac} }{2a} [/tex]
just subsitute and simplify I will only do one in detail since it takes some time
so first one2b^2+10b+12 a=2 b=10 c=12 subsitute x=[tex] \frac{-10- \sqrt{10^2-4(2)(12)} }{2(2)} [/tex] or [tex] \frac{-10+ \sqrt{10^2-4(2)(12)} }{2(2)} [/tex] pemdas
[tex] \frac{-10- \sqrt{10^2-4(2)(12)} }{2(2)} [/tex] do parenthasees or inside exponents (10^2-4(2)(12) =(100-96)=4 square root of 4=2 (-10-2)/(2 times 2)=-12/4=-3 if -10+square root then (-10+2)/(2 times 2)=-8/4=-2 answer is b=-3 or -2
