the equation for the reaction between KOH and HCl is as follows KOH + HCl ---> KCl + H2O the stoichiometry of KOH to HCl = 1:1 the number of KOH moles reacted = 0.5 mol /1000 cm³ * 30 cm³ = 0.015 mol the number of HCl moles reacted = number of KOH moles reacted therefore HCl moles reacted = 0.015 mol the molarity of HCl is 0.2 mol/dm³ 0.2 mol of HCl in - 1000 cm³ Therefore volume required for 0.015 mol = 1000 cm³ / 0.2 mol * 0.015 mol = 75 cm³ Therefore 75 cm³ of HCl is required
