Respuesta :

creeds25
[tex]\frac{ \sqrt{6}- \sqrt{7} }{ \sqrt{6}+ \sqrt{7} } \\ Multiply \ and \ divide \ by \ the \ conjugate. \\ =\frac{ \sqrt{6}- \sqrt{7} }{ \sqrt{6}+ \sqrt{7} } \times \ \frac{ \sqrt{6}- \sqrt{7} }{ \sqrt{6}- \sqrt{7} } \\ =[/tex]
[tex] \frac{( \sqrt{6}- \sqrt{7})^2 }{ \sqrt{6}^2 - \sqrt{7}^2 }} \\ =\frac{( \sqrt{6}- \sqrt{7})^2 }{-1} \\ =-( \sqrt{6}- \sqrt{7})^2 \\ = -( \sqrt{6}^2-2( \sqrt{6} \sqrt{7}+ \sqrt{7}^2 \\ =-(6 -2 \sqrt{42} +7) \\ =-6+2 \sqrt{42}-7 \\ =-13+2 \sqrt{42} \\ Answer: \ -13+2 \sqrt{42}[/tex]
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